Sebanyak 10 mL NaOH 1 M ditambahkan ke dalam 100 mL larutan buffer yang terdiri dari 0,7 M CH3COOH (Kb = 5×10^-10) dan 0,5 M CH3COONa. Nilai pH setelah penambahan NaOH adalah...
A) 10-log5
B) 10
C) 5-log 5
D) 4-log5
E) 4+log5
A) 10-log5
B) 10
C) 5-log 5
D) 4-log5
E) 4+log5
Jawaban:
Penjelasan:
mol CH3COOH = M. V = 0,7 x 100 = 70 mmol
mol CH3COONa = M. V = 0,5 x 100 = 50 mmol
mol NaOH = M. V = 1 x 10 = 10 mmol
CH3COOH + NaOH ---> CH3COONa + H2O
M 70 10 50
R 10 10 10 10
S 60 - 60 10
Kb. Ka = Kw ( Kw = 10^-14 (tetapan))
5. 10^-10. Ka = 10^-14
Ka = 2. 10^-5
[H+] = Ka. (mol asam/mol garam)
= 2.10^-5. (60/60)
= 2. 10^-5
pH = - log H+
= - log 2.10^-5
= 5 - log 2 (D)
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